Superposition: Two Loop Problem叠加:双环问题
To apply the superposition theorem to calculate the current through resistor R1 in the two loop circuit shown, the individual current supplied by each battery is calculated with the other battery replaced by a short circuit. 为应用叠加定理计算图中两回路电路中电阻R₁中的电流,需分别计算每个电池单独作用时流过的电流,此时将另一个电池用短路代替。
![]() Note: To avoid dealing with so many short circuits, any resistor with value zero will default to 1 when a voltage is changed. It can be changed back to a zero value if you wish to explore the effects of short circuits. Ohms and amperes are the default units, but if you put in resistor values in kilohms, then the currents will be milliamperes. 注意:为了避免处理过多的短路,任何值为零的电阻在电压变化时默认为1。如果您希望探索短路的影响,可以将其改回零值。欧姆和安培是默认单位,但如果输入千欧姆的电阻值,电流将显示为毫安。
计算出的电流是 中文译文中的待填/计算数值依次对应:1:i1 2:i2 3:i3。实际数值以上方原输入框为准。 |
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Superposition Theorem叠加定理
To evaluate the separate currents to be combined, replace all other voltage sources by short circuits and all other current sources by open circuits. 为了计算需要结合的各个电流,应将其他所有电压源短路,将其他所有电流源开路。
线性电路中任何一部分的总电流等于各电源单独作用时产生的电流的代数和。 |
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