Thevenin: Two Loop Problem

To apply Thevenin's Theorem to the solution of the two loop problem, consider the current through resistor R₂ below. Replacing the network to the left of R₂ by its Thevenin equivalent simplifies the determination of I₂ .

For 对于

R1

=

Ω, R2

=

Ω, R3

=

Ω,

and voltages 和电压

V1

= V and = V 和 中文译文中的待填/计算数值依次对应：1：v1。实际数值以上方原输入框为准。

V2

= V,

the Thevenin voltage is Thevenin 电压是

= V

since 由于

R1

and 并且

R3

form a simple voltage divider. 组成一个简单的电压分压器。

The Thevenin resistance is Thevenin 电阻是

=

Ω.

This reduces the circuit to a single loop for which the calculated current is

= A

Note: To avoid dealing with so many short circuits, any resistor with value zero will default to 1 when a voltage is changed. It can be changed back to a zero value if you wish to explore the effects of short circuits. Ohms and amperes are the default units, but if you put in resistor values in kilohms, then the currents will be milliamperes.