Bilingual edition: English is preserved and Chinese follows each unit. Terminology uses the confirmed v20260916 glossary; automated semantic review remains traceable.
中英双语版：英文原文完整保留，中文紧随对应单元；术语采用 v20260916 确认表，自动语义审校结果可追溯。

Determining the Mass of an Extended Oject

确定扩展物体的质量

The mass of an extended object can be found by using the conditions for equilibrium of torques. If the object is first balanced to find its center of mass, then the entire weight of the object can be considered to act at that center of mass. If the object is then shifted a measured distance away from the center of mass and again balanced by hanging a known mass on the other side of the pivot point, the unknown mass of the object can be determined by balancing the torques.


But since g appears on both sides of the equation, it can be factored out and just the masses and lengths used for the calculation.

但由于重力加速度g出现在方程的两边，因此可以将其提取出来，仅使用质量和长度进行计算。
m1L1 = m0L2
mass1 x lever1 = mass of rod x lever2

kg x m = kg x m
You may enter data for any of the quantities above. When finished entering data, click on the active text for the quantity you wish to calculate. The data values will not be forced to be consistent until you click on the desired quantity.
一个延伸物体的质量可以通过使用力矩平衡的条件来确定。如果首先将物体平衡以找到其质心，那么物体的整个重量可以认为作用在该质心上。如果物体然后被移离质心一个已测量的距离，并再次通过在支点另一侧悬挂已知质量来平衡，物体的未知质量可以通过平衡力矩来确定。m1 L1 = m0 L2 质量1 × 杠杆1 = 质量 × 杠杆2 kg × m = kg × m 你可以输入上述任何数量的值。输入完毕后，点击你希望计算的量的活动文本。直到你点击所需的量之前，数据值不会被强制保持一致。
中文译文中的待填/计算数值依次对应：1：m1 2：L1 3：m2 4：L2。实际数值以上方原输入框为准。
 Index

Torque equilibrium examples
索引：力矩平衡示例
 
HyperPhysics***** Mechanics
力学
R Nave
 Go Back
返回