Bilingual edition: English is preserved and Chinese follows each unit. Terminology uses the confirmed v20260916 glossary; automated semantic review remains traceable.
中英双语版:英文原文完整保留,中文紧随对应单元;术语采用 v20260916 确认表,自动语义审校结果可追溯。

Moment of Inertia: Cylinder

转动惯量:圆柱体



Moment of inertia about end
关于末端的转动惯量

A solid cylinder of
mass m= kg
and radius R = cm
will have a moment of inertia about its central axis:
Icentral axis = kg m2
通过中心轴的矩等于 kg·m²
中文译文中的待填/计算数值依次对应:1:i1。实际数值以上方原输入框为准。

For a cylinder of
length L = m, the moments of inertia of a cylinder about other axes are shown.
Icentral diameter = kg m2
I中央直径 = kg m²
中文译文中的待填/计算数值依次对应:1:i2。实际数值以上方原输入框为准。
Iend diameter = kg m2
我结束直径 = 千克米平方
中文译文中的待填/计算数值依次对应:1:i3。实际数值以上方原输入框为准。

The moments of inertia for the limiting geometries with this mass are:
Ithin disk diameter = kg m2
我认为盘直径等于千克平方米。
中文译文中的待填/计算数值依次对应:1:i4。实际数值以上方原输入框为准。
Ithin rod end = kg m2
I thin rod end = kg m²
中文译文中的待填/计算数值依次对应:1:i5。实际数值以上方原输入框为准。

一个质量为 m=kg、半径为 R=cm 的实心圆柱体,其绕其轴线的转动惯量为:对于长度为 L=m 的圆柱体,其绕其他轴的转动惯量如图所示。具有此质量的极限几何体的转动惯量为:
中文译文中的待填/计算数值依次对应:1:m 2:R 3:L。实际数值以上方原输入框为准。

Show development of expressions

展示表达式的推导

Hollow cylinder case

空心圆柱体情况
Index

Moment of inertia concepts
索引 转动惯量概念
 
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Moment of Inertia: Cylinder

转动惯量:圆柱体
The expression for the moment of inertia of a solid cylinder can be built up from the moment of inertia of thin cylindrical shells.

Using the general definition for moment of inertia:

使用转动惯量的一般定义:

The mass element can be expressed in terms of an infinitesmal radial thickness dr by

质量元可以表示为通过微小的径向厚度dr来表达的

Substituting gives a polynomial form integral:

代入后得到一个多项式形式的积分:

Show form of integral

展示积分形式
实心圆柱体的转动惯量可以从薄圆柱壳的转动惯量构建起来。
Index

Moment of inertia concepts
索引 转动惯量概念
 
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Moment of Inertia: Hollow Cylinder

转动惯量:空心圆柱



The expression for the moment of inertia of a hollow cylinder or hoop of finite thickness is obtained by the same process as that for a solid cylinder. The process involves adding up the moments of infinitesmally thin cylindrical shells. The only difference from the solid cylinder is that the integration takes place from the inner radius a to the outer radius b:

空心圆柱或圆环(有有限厚度)的转动惯量的表达式是通过与实心圆柱相同的过程得到的。该过程涉及将无限薄的圆柱壳的转动惯量相加。与实心圆柱的不同之处在于,积分的范围是从内半径a到外半径b:

Show development of thin shell integral

展示薄壳积分的发展
Index

Moment of inertia concepts
索引 转动惯量概念
 
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Moment of Inertia: Cylinder About Perpendicular Axis

转动惯量:关于垂直轴的圆柱体

The development of the expression for the moment of inertia of a cylinder about a diameter at its end (the x-axis in the diagram) makes use of both the parallel axis theorem and the perpendicular axis theorem. The approach involves finding an expression for a thin disk at distance z from the axis and summing over all such disks.

推导圆柱体关于其端面直径(图中x轴)的转动惯量的表达式时,同时运用了平行轴定理和垂直轴定理。该方法涉及找到距离轴心距离为z的薄盘的表达式,并对所有这样的薄盘求和。

Obtaining the moment of inertia of the full cylinder about a diameter at its end involves summing over an infinite number of thin disks at different distances from that axis. This involves an integral from z=0 to z=L. For any given disk at distance z from the x axis, using the parallel axis theorem gives the moment of inertia about the x axis.

计算完整圆柱体关于其端面直径的转动惯量需要对无限多个位于不同距离处的薄盘进行求和。这涉及从z=0到z=L的积分。对于任意一个位于距离x轴z处的薄盘,使用平行轴定理可以求得其关于x轴的转动惯量。

Now expressing the mass element dm in terms of z, we can integrate over the length of the cylinder.

将质量元素 dm 表达为 z 的函数,我们可以对圆柱体的长度进行积分。

This form can be seen to be plausible it you note that it is the sum of the expressions for a thin disk about a diameter plus the expression for a thin rod about its end. If you take the limiting case of R=0 you get the thin rod expression, and if you take the case where L=0 you get the thin disk expression.

这种形式可以被看出是合理的,如果你注意到它是薄盘绕其直径的表达式与薄棒绕其一端的表达式的和。如果你取半径R为零的极限情况,就会得到薄棒的表达式;而当长度L为零时,就会得到薄盘的表达式。

The last steps make use of the polynomial forms of integrals.

最后几步利用了积分的多项式形式。

Thin disc moments of inertia

薄盘的惯性矩
Index

Moment of inertia concepts
索引 转动惯量概念
 
HyperPhysics***** Mechanics
力学
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Go Back
返回