Modeling Alpha Half-life

A number of parameters must be calculated to model the barrier penetration which leads to alpha emission . The nuclear influence is assumed to stop sharply when the emitted alpha and the reduced nucleus are just touching each other. Using the nuclear radius relationship, this distance for polonium-212 is 为了建立导致 α 发射的势垒贯穿模型，需要计算若干参数。假设发射出的 α 粒子与衰变后的剩余核刚好接触时，核力作用立即截止。利用核半径关系，钋-212 对应的这一距离为 For a nucleus with atomic mass A, the above relationship is used with A-4. 对于原子质量为 A 的核，上述关系式使用 A-4 进行计算。 For A = , then r = a = fermis. 当质量数 A =【①：a】时，核间距 r = a =【②：r】费米。 中文译文中的待填/计算数值依次对应：1：a 2：r。实际数值以上方原输入框为准。 The height of the barrier at the above distance is calculated as the Coulomb potential of point charges. The charge of the remaining nucleus has been reduced by two by the alpha emission, so that barrier height V(a) is: 在上述距离处，屏障高度由点电荷的库仑势计算得出。由于α衰变，剩余核的电荷已减少两个，因此屏障高度V(a)为： and for Z = it is MeV 当原子序数 Z =【①：z】时，势垒高度为【②：bh】MeV。 中文译文中的待填/计算数值依次对应：1：z 2：bh。实际数值以上方原输入框为准。

The distance at which the Coulomb potential drops to the level of energy of the observed polonium-212 alpha is

For an alpha energy of MeV, the distance is r = b = fermi.

So the width of the polonium-212 barrier is

and the width for the currently modeled nucleus is fermi.

In addition to the tunneling probability calculated below, the alpha emission rate depends upon how many times an alpha particle with this energy inside the nucleus will hit the walls. The velocity of the alpha can be calculated from

since an alpha at this energy is nonrelativistic. The frequency of hitting the walls is then

For the currently modeled nucleus, the frequency is f = x 10^ /s.

To set up the intgration of the tunneling barrier, the first step is to get a differential probability expression. From the tunneling relationship, the probability of tunneling through an infinitesemally thick barrier from r to r+dr is given by

The probability P for penetrating the complete barrier has the form

where G is called the Gamow factor and has the form

The evaluation of this integral gives

Where x = a/b = Q/V(a). The calculated decay constant is equal to this probability times the frequency of impact on the barrier. In the above expression z=2 for an alpha particle, and Z' = Z-z for the the parent nucleus after emission. For the parameters given, the probability is

= x10^

and the resulting decay constant is

This leads to a calculated halflife of