Resolvance of Grating光栅分辨率
Resolvance or "chromatic resolving power" for a device used to separate the wavelengths of light is defined as 用于分离光的波长的设备的分辨力或‘色分辨力’定义为
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The limit of resolution is determined by the Rayleigh criterion as applied to the diffraction maxima, i.e., two wavelengths are just resolved when the maximum of one lies at the first minimum of the other.
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Examples of Resolvance分辨率的例子
A standard benchmark for the resolvance of a grating or other spectroscopic instrument is the resolution of the sodium doublet. The two sodium "D-lines" are at 589.00 nm and 589.59 nm. Resolving them corresponds to resolvance 衍射光栅或其他光谱仪器的分辨率标准基准是钠双线的分辨率。钠的两个'D线'位于589.00纳米和589.59纳米处。分辨这两条线对应于分辨能力
![]() Another standard example is the resolution of the hydrogen and deuterium lines, often done with a Fabry-Perot Interferometer. The red lines of hydrogen and deuterium are at 656.3 nm and 656.1 nm, respectively. This requires a resolvance of 另一个标准例子是氢线和氘线的分辨,通常使用法布里-珀罗干涉仪来实现。氢和氘的红光谱线分别位于656.3纳米和656.1纳米处,这需要一定的分辨能力。
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Resolvance of Grating光栅分辨率
This gives the basic ideas, but the assumptions are shaky, so you might want a real derivation. 这给出了基本概念,但假设不够牢固,因此你可能希望有一个真实的推导。
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Resolvance of Grating光栅分辨率
![]() This approach to the resolvance of a grating has made use of the fact that the phase is a continuous variable which can be represented analytically, and that the differential of this variable is also well-defined. Since the Rayleigh criterion places the peak of one order at the first minimum of the adjacent order, the phase associated with being "just resolved" is determined to be 2π/N. Taking the differential of that phase gives an expression which contains the differential of wavelength dλ which allows the quantity λ /dλ to be evaluated. In practice, the resolvance is stated in the form R=λ /Δλ for applications like the observation of the sodium doublet. In that case we know the wavelength difference to be Δλ = .59 nm, so the resolvance can help us to anticipate whether a particular diffraction grating could resolve that difference. 这种方法利用了衍射光栅的分辨能力,其关键在于相是一个连续变量,可以解析地表示,且该变量的微分也具有明确的定义。由于瑞利判据将一个光谱线的峰值置于相邻光谱线的第一个最小值处,因此“刚刚分辨”时的相被确定为2π/N。对该相的微分给出了一个包含波长微分dλ的表达式,从而可以计算出λ/dλ的值。在实际应用中,分辨能力通常以R=λ/Δλ的形式给出,例如用于观测钠双线。在这种情况下,已知波长差Δλ=0.59 nm,因此分辨能力可以帮助我们判断特定的衍射光栅是否能够分辨这一差异。 |
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