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The Bug-Rivet Paradox

虫-钉子悖论

The bug-rivet paradox is a variation on the twin paradox and is similar to the pole-barn paradox in that the ideas of simultaneity in relativity must be addressed. The fact that two events are simultaneous in one frame of reference does not imply that they are simultaneous as seen by an observer moving at a relativistic speed with respect to that frame.

虫-铆悖论是双生子悖论的一个变种,它与杆-车库悖论类似,都必须考虑相对论中的同时性问题。在一个参考系中两个事件是同时发生的,并不意味着在另一个以相对论速度运动相对于该参考系的观察者看来它们也是同时发生的。

To calculate the times for the two frames of reference, consider the rivet entering the hole and set t=t'=0 at that instant and x=x'=0 to establish the coordinate system. In the events described below, x' and t' refer to the rivet frame while x and t refer to the bug frame. The relativity factor γ = 2.29 and the Lorentz transformation is used to transform quantities from one frame to the other.

为计算两个参考系的时间,考虑钉子进入孔中的情况,在该时刻将t=t'和x=x'设为零,以建立坐标系。在下面描述的事件中,x'和t'指的是钉子的参考系,而x和t指的是虫的参考系。相对论因子γ = 2.29,使用洛伦兹变换将量从一个坐标系转换到另一个坐标系。

Rivet frame of reference

铆钉参考系

The rivet is considered to the be the reference frame, and x' and t' are used for positions and times.

铆钉被视为参考系,x'和t'用于表示位置和时间。
  • End of rivet enters hole: t' = 0
    铆钉进入孔底:t' = 0
  • Rivet head hits wall: t' = 0.8 cm/0.9c = 29.63 ps
    铆钉头撞墙:t' = 0.8 cm/0.9c = 29.63 ps
  • Rivet end hits length-contracted bottom of hole: t' = 1 cm/0.9cg = 16.14 ps
    铆钉头击中长度收缩的孔底:t' = 1 cm/0.9c = 16.14 ps

The end of the rivet hits the bottom of the hole before the head of the rivet hits the wall. So it looks like the bug is squashed.

铆钉末端在铆钉头碰到墙之前已经进入了孔底。因此看起来虫子被压扁了。

Transforming the times to the bug's frame of reference:
  • End of rivet enters hole: t = 0
    铆钉进入孔底的时间:t = 0
  • Rivet head hits wall: t = γ(t'+vx'/c2) = 2.29(29.63 ps + (-0.9c)(0.8 cm)/c2) = 12.9 ps
    铆钉头撞墙:t = γ(t' + vx'/c²) = 2.29(29.63 ps + (-0.9c)(0.8 cm)/c²) = 12.9 ps
  • Time for rivet to reach end of hole: t = 2.29(16.14 ps) = 37.04 ps
    铆钉到达孔底所需时间:t = 2.29(16.14 ps) = 37.04 ps

The bug disagrees with this analysis and finds the time for the rivet head to hit the wall is earlier than the time for the rivet end to reach the bottom of the hole. The paradox is not resolved.

这只虫子不同意这一分析,认为rivet头击中墙的时间早于rivet尾端到达孔底的时间。这个悖论并未得到解决。

Bug frame of reference

虫洞参考系
  • Front of rivet enters hole: t = 0
  • Head of rivet hits wall: t = 0.8 cm/0.9cγ = 12.91 ps
    铆钉头撞墙:t = 0.8 cm/0.9cγ = 12.91 ps
  • 铆钉前端进入孔内:t = 0

All this is nonsense from the bug's point of view. The rivet head hits the wall when the rivet end is just 0.35 cm down in the hole! The rivet doesn't get close to the bug.

从虫子的角度看,这一切都是胡说八道。当铆钉头击中墙壁时,铆钉末端才刚进入孔中0.35厘米!铆钉根本无法接近虫子。
将时间变换到虫子的参考系中:

Transforming the times measured in the bug's frame of reference to the rivet frame:
  • Rivet head impact time t' = γ(12.9 ps) = 29.63 ps
    铆钉头冲击时间 t' = γ(12.9 ps) = 29.63 ps
  • Rivet end in bug frame is simultaneously at x=-.35 cm, but it is not simultaneous in the rivet frame. Transforming gives t' =γ(12.9 ps - .9c(.0035)/c2) = 5.63 ps.
    在铆钉框架中,铆钉末端同时位于x=-0.35 cm处,但在虫洞框架中并非同时。变换后得到t' = γ(12.9 ps - 0.9c(0.0035)/c²) = 5.63 ps。
  • If you try to find a rivet frame time when the rivet end hits the bottom of the hole, x = -1 cm, t' =γ(37.04 ps - .9c(.01)/c2) = 16.14 ps.
    如果你试图找到一个铆钉框架的时间,当铆钉末端击中孔底时,x = -1 cm,t' = γ(37.04 ps - 0.9c(0.01)/c² ) = 16.14 ps.

Transforming times from the bug frame to the rivet frame gives a time for the end to reach -0.35 cm before the rivet head hits, and even suggests that it reaches the bottom of the hole before the rivet head hits. The paradox is not resolved.

将虫洞参考系中的时间转换为铆钉参考系,得到一个结果:钉头撞击前,钉尾到达孔底的时间为-0.35 cm,甚至暗示钉尾在钉头撞击前已到达孔底。这个悖论仍未得到解决。

The Pole-Barn Paradox
杆仓悖论
将虫子参考系中测量的时间转换为rivet参考系中的时间:
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