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Neutrino Transparency Temperature

中微子透明温度

In evaluating the energy density in the background radiation in the universe, it is necessary to include both the photon 3K background and the neutrino background. The neutrino transparency point occurred before the photon transparency which gives us the microwave background radiation. In estimating that transparency temperature for neutrinos, Weinberg uses an entropy argument.

在评估宇宙背景辐射中的能量密度时,必须包括光子3K背景和中微子背景。中微子透明点发生在光子透明点之前,这为我们提供了微波背景辐射。在估算中微子的透明温度时,Weinberg使用了熵的论点。

Presuming that the expanding universe did so under conditions of thermal equilibrium, the second law of thermodyamics suggests that entropy remained constant. The entropy per unit volume at temperature T can be approximated by

假设立宇宙在热平衡条件下膨胀,热力学第二定律表明熵保持不变。温度为T时,单位体积的熵可近似表示为

S α NTT3

where NT is the effective number of species in thermal equilibrium . This includes only those particles which have a critical temperature less than T, i.e., they can be formed from the current level of thermal energy. To keep the entropy constant for an expanding universe, the entropy must be proportional to the inverse cube of the volume so that

其中N_T是热平衡下的有效粒子种类数。这仅包括那些临界温度低于T的粒子,即它们可以从当前的热能水平形成。为了保持熵恒定,随着宇宙的膨胀,熵必须与体积的立方倒数成正比,所以

SR3 α NTT3R3 = constant

SR 3 α N T T 3 R 3 = 常数

where R can be taken to be the separation between typical particles.

其中 R 可以视为典型粒子之间的分离距离。

After the neutrinos in the early universe went out of equilibrium, only electrons, positrons and photons were left in thermal equilibrium, and that changed with the annihilation of the electrons and positrons at about 5 x 109K. To evaluate the effect on the temperature, one must examine the number of species which goes into the entropy expression. The effective numbers are:

在早期宇宙中中微子脱离平衡后,只剩下电子、正电子和光子处于热平衡状态,这一状态在约5×10⁹ K时因电子和正电子的湮灭而发生变化。要评估这一影响对温度的作用,必须考察进入熵表达式的粒子种类数量。有效数为:
Nelectron,positron = 2 x 2 x 7/8 = 7/2
Nphoton = 2 x 1 x 1 = 2
N 电子、正电子 = 2 × 2 × 7/8 = 7/2 N 光子 = 2 × 1 × 1 = 2
The effective numbers for the particles are calculated as the product of the three factors:
  • 2 if particle has distinct antiparticle, 1 if not.
    若粒子有 distinct 的反粒子,则为 2;否则为 1。
  • Number of possible orientations of the particles spin.
    粒子自旋可能的取向数目
  • 7/8 if particle subject to Pauli exclusion principle, 1 if not.
    若粒子服从泡利不相容原理,则为7/8;若不服从,则为1。
粒子的有效数目由三个因素的乘积计算得到:

So with the electron-positron annihilation, the effective numbers changed.

因此,电子-正电子湮灭后,有效数量发生了变化。
Nbefore = 7/2 + 2
N before = 7/2 + 2(专名或术语)
Nafter = 2
N after = 2(专名或术语)

By the constancy of entropy:

通过熵的恒定性:
11/2 (TR)3before = 2(TR)3after

The energy release of the electron-positron annihilation changes the quantity TR by the factor:

电子-正电子湮灭释放的能量使量TR乘以一个因子:
(TRafter/TRbefore) = (11/4)1/3 = 1.401

This is the factor which allows us to calculate the effective temperature of the neutrino background. We reason that before the electron-positron annihilation, the temperature for the photons and neutrinos was the same. Since the neutrinos had decoupled at that time, the product TνR for the neutrinos remains equal to the product TeR before the annihilation. For the present universe this gives

这个因子使我们能够计算中微子背景的有效温度。我们推断,在电子-正电子湮灭之前,光子和中微子的温度是相同的。由于中微子在那时已经脱离耦合,因此中微子的T ν R乘积在湮灭前保持不变。对于现在的宇宙,这给出了
Tν = Tphoton(4/11)1/3 = 2.725 K/1.401 = 1.9K

for the effective temperature of the neutrino background.

对于中微子背景的有效温度。

The amount of energy in this neutrino background can be estimated with the use of the Stefan- Boltzmann law, treating the neutrinos as massless particles at 1.9K. The ratio of the neutrino energy density in this equilibrium radiation can be expressed as a fraction of the photon energy density of about 0.25 MeV/m3

这种中微子背景中的能量可以用斯蒂芬-玻尔兹曼定律估算,将中微子视为在1.9K时的无质量粒子。这种平衡辐射中的中微子能量密度与光子能量密度之比可表示为约0.25 MeV/m³的分数。
ρneutrino = ρphoton(7/4)(1.96 K/2.74 K)4 = 0.454 ρphoton = 0.11 MeV/m3

We used the fact that the neutrinos are more numerous by the factor (7/2)/2 =7/4, there being a factor of 2 for the effective number of photons because of two polarization states. The combined energy density in the background radiation is then

我们利用了中微子数量比光子多一个因子7/4的事实,这是因为光子由于有两个极化状态,有效数量乘以了2。背景辐射中的总能量密度则为
Relate to temperature and expansion time
与温度和膨胀时间相关
11/2 (TR) 3 before = 2(TR) 3 after (TR after /TR before ) = (11/4) 1/3 = 1.401 T ν = T photon (4/11) 1/3 = 2.725 K/1.401 = 1.9K ρ neutrino = ρ photon (7/4)(1.96 K/2.74 K)4 = 0.454 ρ photon = 0.11 MeV/m 3(专名或术语)
Index

Reference
Weinberg
First 3 Minutes
索引参考 Weinberg 第三分钟
 
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