Transformer

A transformer makes use of Faraday's law and the ferromagnetic properties of an iron core to efficiently raise or lower AC voltages. It of course cannot increase power so that if the voltage is raised, the current is proportionally lowered and vice versa.

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Transformer and Faraday's Law

Ideal Transformer Calculation

Primary Primary voltage = VP = volts. 初级电压 = V_P = 伏特。 中文译文中的待填/计算数值依次对应：1：v1。实际数值以上方原输入框为准。 Primary current = IP = amps 主电流 = I_P = 安 中文译文中的待填/计算数值依次对应：1：i1。实际数值以上方原输入框为准。 Primary turns = NP =turns 初级线圈匝数 = N_P = 匝数 中文译文中的待填/计算数值依次对应：1：n1。实际数值以上方原输入框为准。 主要的 Secondary Secondary voltage = VS = volts 次级电压 = V_S = 伏 中文译文中的待填/计算数值依次对应：1：v2。实际数值以上方原输入框为准。 Secondary current = IS = amps 次级电流 = I_S = 安培 中文译文中的待填/计算数值依次对应：1：i2。实际数值以上方原输入框为准。 Secondary turns = NS = turns 次级线圈匝数 = N_S = 匝数 中文译文中的待填/计算数值依次对应：1：n2。实际数值以上方原输入框为准。 Load resistor = R = ohms 负载电阻 = R = 欧姆 中文译文中的待填/计算数值依次对应：1：r。实际数值以上方原输入框为准。 次级

For an ideal transformer: Power Power used = PP = PS = watts 使用的功率 = P P = P S = 瓦特 中文译文中的待填/计算数值依次对应：1：p。实际数值以上方原输入框为准。 功率 The ideal transformer neglects losses to resistive heating in the primary coil and assumes ideal coupling to the secondary (i.e., no magnetic losses). 理想变压器忽略了初级线圈中电阻发热的损耗，并假设初级与次级之间有理想的耦合（即没有磁滞损耗。 对于理想变压器：

Notes: For this exploratory calculation, you may enter data for any parameter except the power. Then click on the active text for the parameter you wish to calculate; values will not be forced to be consistent until you do. For primary calculations, the voltage and number of turns in the secondary will be considered to be established and vice versa. Default values will be entered for unspecified parameters, but all values except the power may be changed.