Relativistic Velocity Transformation相对论速度变换
No two objects can have a relative velocity greater than c! But what if I observe a spacecraft traveling at 0.8c and it fires a projectile which it observes to be moving at 0.7c with respect to it!? Velocities must transform according to the Lorentz transformation, and that leads to a very non-intuitive result called Einstein velocity addition. 没有两个物体可以有超过光速的相对速度!但如果我观察一个以0.8c速度飞行的航天器,并且它发射出一个以0.7c速度运动的弹体(相对于它自己),那么速度必须按照洛伦兹变换进行变换,这会导致一个非常非直观的结果,称为爱因斯坦速度相加。
![]() Just taking the differentials of these quantities leads to the velocity transformation. Taking the differentials of the Lorentz transformation expressions for x' and t' above gives 仅仅对这些量求微分就得到速度变换。对上述洛伦兹变换表达式中的x'和t'求微分就得到
![]() Putting this in the notation introduced in the illustration above: ![]() The reverse transformation is obtained by just solving for u in the above expression. Doing that gives 逆变换 simply 通过解上述表达式中的 u 得到。这样做得到
![]() Applying this transformation to the spacecraft traveling at 0.8c which fires a projectile which it observes to be moving at 0.7c with respect to it, we obtain a velocity of 1.5c/1.56 = 0.96c rather than the 1.5c which seems to be the common sense answer. 将这一变换应用于以0.8c速度飞行的航天器,该航天器观察到一个弹体以0.7c相对于它运动,我们得到弹体的速度为1.5c/1.56 = 0.96c,而不是直觉上似乎合理的1.5c。
将此内容放入上述示意图中引入的符号体系中: |
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