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Mossbauer Effect in Iron-57

钼-57的莫塞莱效应

The study of the Mossbauer effect in Iron-57 has been very fruitful because of the narrow natural linewidth of the 14.4 keV transition. This transition is characterized by:

对铁-57的莫塞莱效应的研究取得了丰硕成果,这是因为其14.4 keV跃迁具有很窄的自然线宽。该跃迁的特点是:

While one atom can emit a photon which is absorbed by the reverse transition in an identical atom a short distance away (resonance fluorescence), the same cannot happen for nuclear transitions from isolated nuclei. The reason is the large recoil energy compared to the natural linewidth of the transition.

虽然一个原子可以发射一个光子,该光子被远处另一个相同原子的反向跃迁吸收(荧光),但这种情况不适用于孤立核的核跃迁。原因在于跃迁的反冲能量远大于自然线宽。

Using the iron as an example, the 14.4 keV gamma ray has momentum pc=14.4 keV. The recoil momentum of the emitting iron nucleus must match that if it acts as an isolated particle. The recoil energy can be calculated from the momentum, and it is usually convenient in such cases to put everything in electron volts.

以铁为例,14.4 keV的伽马射线具有动量pc=14.4 keV。如果铁核作为孤立粒子作用,其反冲动量必须与之匹配。反冲能量可以从动量计算得出,通常在这种情况下将所有量转换为电子伏特会更方便。

The energy of recoil of the iron-57 nucleus is

铁-57核的反冲能是
Iron nuclear data
铁核数据

This is five orders of magnitude greater than the natural linewidth of the iron transition which produced the photon. This recoil energy reduces the photon energy by this amount as seen by a potential absorbing nucleus at rest.

这个能量比铁跃迁所产生的光子的自然线宽大五个数量级。这种反冲能量会使静止的潜在吸收核所观测到的光子能量减少这一数量。

To get resonance absorption, you have two options: nail down the nucleus in a crystal lattice so that it has almost no recoil, or move the source and absorber relative to each other so that the Doppler shift of the photon moves it to the necessary energy for absorption.

要实现共振吸收,有两种选择:将核钉在晶体晶格中,使其几乎不产生反冲,或者使源和吸收体相对运动,使得光子的多普勒频移使其能量达到吸收所需的能量。

The Doppler shift of a photon is a relativistic Doppler shift given by

光子的多普勒频移是相对论多普勒频移,其表达式为

If v/c<<1 then this may be simplified by

如果 v/c 远小于 1,则可以简化为

The source velocity necessary to shift the photon to resonance absorption energy is

While this is possible, and was done with centrifuge tips, there is generally a better way.

虽然这可行,而且曾用离心机尖端实现,但通常有更好的方法。

Mossbauer found that if he cooled the emitter, you could reach a condition where the emitting nucleus could not recoil by itself. Qualitatively, the reason is that at sufficiently low temperatures an atom in a crystal lattice cannot recoil individually. The quantization of the vibrational states of the lattice causes the energy of recoil to be absorbed by the lattice as a whole.

莫斯巴auer发现,如果他冷却发射体,可以达到一种条件,使得发射的核无法自行 recoil。定性地说,原因在于在足够低的温度下,晶体中的原子无法单独 recoil。晶格振动状态的量子化导致 recoil 的能量被整个晶格吸收。

It was a great breakthrough to realize that you could get resonance absorption of gamma rays by putting the source nuclei in a crystal and cooling it. To see how many iron nuclei would have to recoil together to keep the gamma within the natural linewidth:

认识到将源核置于晶体并冷却它就能实现伽马射线的共振吸收,这是一个重大突破。要看到多少铁核需要一起反冲以保持伽马射线在自然线宽内:

Compared to Avogadro's number, that's not very many. In fact, it is a speck of matter too small to be seen in an optical microscope. It would follow that any tiny crystal within a cobalt-57-containing piece of iron would meet the conditions for resonance absorption if cooled sufficiently.

与阿伏伽德罗常数相比,这并不算很多。事实上,它是一个太小的物质,无法在光学显微镜下被看到。因此,如果将含有钴-57的铁件冷却到足够低的温度,其中任何微小的晶体都会满足共振吸收的条件。

It was established that you can produce resonant gamma absorption by cooling the iron sample. You can also destroy that resonance by moving the source relative to the absorber. Returning to the Doppler expression

已确认可以通过冷却铁样品来产生共振的伽马吸收。你也可以通过将源相对于吸收体移动来破坏这种共振。回到多普勒表达式

gives v=0.0002 m/s to produce enough Doppler shift of the emitted gamma to detune the resonant absorption. This is more than a curiosity-- this is the basis for an incredibly sensitive instrument. Pound and Rebka needed just such an instrument to test the gravitational red shift.

给发射的伽马射线产生足够的多普勒频移以调谐共振吸收,使其速度达到0.0002 m/s。这不仅仅是个奇闻——这是极其灵敏的仪器的基础。庞德和雷伯卡正是需要这种仪器来检验引力红移现象。
Iron nuclear Zeeman effect
铁核塞曼效应
将光子移至共振吸收能所需的源速度是
Index

References
Rohlf
Sec 11.7

Tipler & Llewellyn
Sec 11.4
索引 参考 Rohlf 第11章第7节 Tipler & Llewellyn 第11章第4节
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