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Discovery of the Neutron

中子的发现

It is remarkable that the neutron was not discovered until 1932 when James Chadwick used scattering data to calculate the mass of this neutral particle. Since the time of Rutherford it had been known that the atomic mass number A of nuclei is a bit more than twice the atomic number Z for most atoms and that essentially all the mass of the atom is concentrated in the relatively tiny nucleus. As of about 1930 it was presumed that the fundamental particles were protons and electrons, but that required that somehow a number of electrons were bound in the nucleus to partially cancel the charge of A protons. But by this time it was known from the uncertainty principle and from "particle-in-a-box" type confinement calculations that there just wasn't enough energy available to contain electrons in the nucleus.

值得注意的是,中子直到1932年才被发现,当时詹姆斯·查德威克利用散射数据计算了这个中性粒子的质量。自卢瑟福时代以来,人们已知道大多数原子的核质量数A略大于原子序数Z的两倍,并且原子的大部分质量都集中在相对微小的核中。到大约1930年时,人们假设基本粒子是质子和电子,但这就要求 somehow 一些电子被束缚在核中以部分抵消A个质子的电荷。但到那时,人们已从不确定性原理和“粒子在盒中”类型的束缚计算中知道,根本没有足够的能量将电子束缚在核中。

A rough scale of the energy required for the confinement of a particle to a given dimension can be obtained by setting the DeBroglie wavelength of the particle equal to that dimension. For example, if we presume that the dimension of a hydrogen atom is about 0.2 nm, then the corresponding confinement energy is about 38 eV, the correct order of magnitude for atomic electrons. But to confine an electron to a nuclear dimension of about 5 fermis requires an energy of about 250 MeV. The maximum available confinement energy from the electrical attraction to the nucleus is given by

一个粒子被限制在给定维度内的所需能量的粗略尺度可以通过将粒子的德布罗意波长设为该维度来获得。例如,如果我们假设氢原子的尺寸约为0.2纳米,那么相应的束缚能量约为38 eV,这与原子电子的正确数量级相符。但要将电子束缚在约5费米的核尺寸上,则需要约250 MeV的能量。从电荷与核之间的静电吸引力所能提供的最大束缚能量为
Electrostatic
potential energy
静电势能

So it is clear that there are no electrons in the nucleus.

显然,原子核中没有电子

An experimental breakthrough came in 1930 with the observation by Bothe and Becker that bombardment of beryllium with alpha particles from a radioactive source produced neutral radiation which was penetrating but non-ionizing. They presumed it was gamma rays, but Curie and Joliot showed that when you bombarded a paraffin target with this radiation, it ejected protons with energy about 5.3 MeV. This proved to be inconsistent with gamma rays, as can be shown from momentum and energy analysis:

1930年,Bothe和Becker的实验观察到,用放射性源产生的alpha粒子轰击铍时,产生了中性辐射,这种辐射具有穿透性但不带电。他们假设这是伽马射线,但Curie和Joliot证明当这种辐射轰击石蜡靶时,会发射出能量约为5.3 MeV的质子。这与伽马射线相矛盾,可以从动量和能量分析中得到证明:

This analysis follows that for a headon elastic collision where a small particle strikes a much more massive one. Again, the necessary energy for the gamma ray explanation was much greater than any energy observed to be available from the nucleus, so the neutral radiation must be some kind of neutral particle.

这种分析遵循一个正面对撞的弹性碰撞情况,其中一个小粒子撞击一个质量远大的物体。同样,伽马射线解释所需的能量远大于从原子核中观测到的任何能量,因此中性辐射必须是一种中性粒子。

The 5.3 MeV energy of the ejected protons could be easily explained if the neutral particle had a mass comparable to that of the proton. For headon collisions, this would require only 5.3 MeV from the neutral particle, a value in the range of observed nuclear particle emissions.

被弹出的质子的5.3 MeV能量可以很容易地解释为中性粒子的质量与质子相当。对于正面对撞,这只需要中性粒子提供5.3 MeV的能量,这个值在观察到的核粒子发射范围内。

Chadwick was able to prove that the neutral particle could not be a photon by bombarding targets other than hydrogen, including nitrogen, oxygen, helium and argon. Not only were these inconsistent with photon emission on energy grounds, the cross-section for the interactions was orders of magnitude greater than that for Compton scattering by photons.

恰德威克通过用除氢以外的靶材(包括氮、氧、氦和氩)进行轰击,证明了中性粒子不可能是光子。不仅这些结果与光子发射在能量方面的解释相矛盾,这些相互作用的截面也比光子的康普顿散射截面大几个数量级。

The task which remained for Chadwick was that of determining the mass of the neutral particle. He chose to bombard boron with alpha particles and analyze the interaction of the neutral particles with nitrogen. These particlular targets were chosen partly because the masses of boron and nitrogen were well known. Conservation of energy applied to the combined interactions gives the following expressions:

恰德威克剩下的任务是确定中性粒子的质量。他选择用α粒子轰击硼,并分析中性粒子与氮的相互作用。这些特定的目标部分是因为硼和氮的质量已知。能量守恒应用于这些相互作用的总和,给出了以下表达式:

Solving for the mass energy of the neutron gives

求解中子的质量能

The remaining unknown on the right hand side of the equation is the speed of the neutron. Assuming that the neutron mass was close to that of the proton, Chadwick bombarded hydrogen atoms with his produced neutrons to learn the speed of the protons after the collisions. Then setting the neutron speed equal to those proton speeds, he used the above energy expression to get a neutron mass of 938 +/- 1.8 MeV. With a consistent set of experiments, Chadwick had obtained the first value for the neutron mass which compared well with the presently accepted value of 939.57 MeV.

方程右边剩余的未知数是中子的速率。假设中子的质量接近质子的质量,查德威克用他产生的中子轰击氢原子,以了解碰撞后质子的速率。然后将中子的速率设为质子的速率,他利用上述能量表达式得到中子的质量为938±1.8 MeV。通过一致的实验集,查德威克得到了中子质量的第一个值,该值与目前接受的值939.57 MeV相比较良好。
The search for the basic structure of matter.
探索物质的基本结构
Index

Particle concepts

References
Rohlf
Ch. 11

Krane, Intro Nuclear Physics
Ch. 12
索引 粒子概念 参考文献 Rohlf 第11章 Krane,《介绍性核物理》第12章
 
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