Bilingual edition: English is preserved and Chinese follows each unit. Terminology uses the confirmed v20260916 glossary; automated semantic review remains traceable.
中英双语版:英文原文完整保留,中文紧随对应单元;术语采用 v20260916 确认表,自动语义审校结果可追溯。

Show all 26 classical distributions
显示所有26个经典分布

How many ways can you distribute 9 units of energy among 6 identical, indistinguishable fermions?

如何将9个单位的能量分配给6个相同的、不可区分的费米子?

Fermi-Dirac statistics differ dramatically from the classical Maxwell-Boltzmann statistics in that fermions must obey the Pauli exclusion principle. Considering the particles in this example to be electrons, a maximum of two particles can occupy each spatial state since there are two spin states each. Whereas there were 26 possible configurations for distinguishable particles, these are reduced to the 5 states which have no more than two particles in each state.

费米-狄拉克统计与经典的麦克斯韦-玻尔兹曼统计有显著不同,因为费米子必须遵守泡利不相容原理。考虑到这些粒子为电子,每个空间状态最多只能容纳两个粒子,因为每个空间状态有自旋的两个状态。而对于可区分粒子来说,有26种可能的配置,这些配置被减少到只有5种,每种状态中最多有两个粒子。

Evaluating the average occupancy of each energy state is much simpler than in the Maxwell-Boltzmann example since each macrostate has a weight of 1. The average occupancy is just the sum of the numbers of particles in a given energy state over all the 5 distributions divided by 5.

Evaluate the average for each energy state.
计算每个能态的平均值。
Compare with Maxwell-Boltzmann example.
与麦克斯韦-玻尔兹曼示例进行比较。
评估每个能量状态的平均占据数比Maxwell-Boltzmann的例子要简单得多,因为每个宏观状态的权重为1。平均占据数只是将所有5种分布中特定能量状态的粒子数相加后除以5。
Index

Reference
Blatt
Ch. 11
索引参考Blatt第11章
 
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The average distribution of 9 units of energy among 6 identical particles

9个单位的能量在6个相同粒子间的平均分布
EAverage
number
Maxwell-
Boltzmann
平均麦克斯韦-玻尔兹曼数
Average
number
Bose-
Einstein
平均数玻色-爱因斯坦
Average
number
Fermi-
Dirac
费米-狄拉克平均数
0
2.143
2.269
1.8
1
1.484
1.538
1.6
2
0.989
0.885
1.2
3
0.629
0.538
0.8
4
0.378
0.269
0.4
5
0.210
0.192
0.2
6
0.105
0.115
0
7
0.045
0.077
0
8
0.015
0.038
0
9
0.003
0.038
0

For fermions, there are only 5 possible distributions of 9 units of energy among 6 particles compared to 26 possible distributions for classical particles. To get a distribution function of the number of particles as a function of energy, the average population of each energy state must be taken. The average for each of the 9 states is shown above compared to the results obtained by Maxwell-Boltzmann statistics and Bose-Einstein statistics .

对于费米子,9个单位能量在6个粒子之间的分布只有5种可能,而经典粒子则有26种可能。要得到粒子数随能量变化的分布函数,必须计算每个能量状态的平均占据数。上述所示的是9个状态的平均值,与麦克斯韦-玻尔兹曼统计和玻色-爱因斯坦统计的结果相比较。

Low energy states are less probable with Fermi-Dirac statistics than with the Maxwell-Boltzmann statistics while mid-range energies are more probable. While that difference is not dramatic in this example for a small number of particles, it becomes very dramatic with large numbers and low temperatures. At absolute zero all of the possible energy states up to a level called the Fermi energy are occupied, and all the levels above the Fermi energy are vacant.

低能态在费米-狄拉克统计下比在麦克斯韦-玻尔兹曼统计下更不 probable,而中等范围的能量更 probable。虽然在这个例子中,对于少量粒子,这种差异并不显著,但当粒子数很大且温度很低时,这种差异变得非常显著。在绝对零度时,所有可能的能量态直到一个称为费米能的能级都被占据,而所有高于费米能的能级都是空的。
Index

Reference
Blatt
Ch. 11
索引参考Blatt第11章
 
HyperPhysics***** Quantum Physics
HyperPhysics ***** 量子物理
R Nave
Go Back
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