Helium Energy Levels氦的能量级
The electron energy levels for a helium atom demonstrate a number of features of multi-electron atoms. 氦原子的电子能级展示了多电子原子的一些特征。
One electron is presumed to be in the ground state, the 1s state. An electron in an upper state can have spin antiparallel to the ground state electron (S=0, singlet state, parahelium) or parallel to the ground state electron (S=1, triplet state, orthohelium).
一个电子被假定处于基态,即1s态。处于激发态的电子可以有自旋与基态电子反平行(S=0,单重态,para氦)或平行(S=1,三重态,ortho氦)。 |
Index Atomic Structure Concepts 索引 原子结构概念 | |||||||
|
Go Back
返回 |
Orthohelium and Parahelium Energy Levels正氦和正氦能级
In the helium energy level diagram, one electron is presumed to be in the ground state of a helium atom, the 1s state. An electron in an upper state can have spin antiparallel to the ground state electron (S=0, singlet state, parahelium) or parallel to the ground state electron (S=1, triplet state, orthohelium). 在氦的能量级图中,假设有电子处于氦原子的基态(1s态)。处于激发态的电子可以有自旋与基态电子反平行(S=0,单重态,para氦)或平行(S=1,三重态,ortho氦)。
It is observed that the orthohelium states are lower in energy than the parahelium states. The explanation for this is: 观察到正氦态的能级比正氦态的能级更低。其解释是:
This effect is sometimes called the "spin-spin interaction" and is addressed by Hund's Rule #1 . It is part of the understanding of the ordering of energy levels in multi-electron atoms. 这种效应有时被称为“自旋-自旋相互作用”,并由洪德规则#1加以解释。它是理解多电子原子中能级排列的理解的一部分。
|
Index Reference Rohlf Ch 9 索引参考Rohlf第9章 | ||
|
Go Back
返回 |
Helium Energy Levels氦的能量级
The helium ground state consists of two identical 1s electrons. The energy required to remove one of them is the highest ionization energy of any atom in the periodic table: 24.6 electron volts. The energy required to remove the second electron is 54.4 eV, as would be expected by modeling it after the hydrogen energy levels. The He+ ion is just like a hydrogen atom with two units of charge in the nucleus. Since the hydrogenic energy levels depend upon the square of the nuclear charge, the energy of the remaining helium electron should be just 4x(-13.6 eV) = -54.4 eV as observed. 氦的基态由两个相同的1s电子组成。移除其中一个电子所需能量是元素周期表中任何原子的最高电离能:24.6电子伏特。移除第二个电子所需能量为54.4 eV,这与将它建模为氢原子能级相符合。He+离子就像一个氢原子,其核荷为两单位。由于氢样能级取决于核电荷的平方,剩余氦原子的电子能量应为4×(-13.6 eV) = -54.4 eV,如观察到的那样。
The fact that the second electron is less tightly bound can be interpreted as a shielding effect; the other electron partly shields the second electron from the full charge of the nucleus. Its energy can be used to model the effective shielding as follows. 第二个电子结合得不那么紧密的事实可以解释为屏蔽效应;其他电子部分地屏蔽了第二个电子,使其免受核电荷的全部作用。其能量可以用来建模这种有效的屏蔽作用如下。
![]() Another way to view the energy is to say that the repulsion of the electrons contributes a positive potential energy which partially offsets the negative potential energy contributed by the attractive electric force of the nuclear charge. The description of any electron in a multi-electron atom must find a way to characterize the effect of the other electrons on the energy. 另一种看待能量的方式是说,电子之间的排斥作用贡献了一个正的势能,这在一定程度上抵消了由核电荷的吸引力所贡献的负势能。在多电子原子中,任何电子的描述都必须找到一种方式来表征其他电子对其能量的影响。
|
Index Reference Rohlf Ch 9 索引参考Rohlf第9章 | |||
|
Go Back
返回 |